Search found 35 matches

by Fulcrum
Mon Jul 01, 2013 11:11 am
Forum: .NET
Topic: Axis Legend
Replies: 4
Views: 6380

Re: Axis Legend

thanks Sandra, the 1st solution made what I want
by Fulcrum
Fri Jun 28, 2013 8:29 am
Forum: .NET
Topic: Axis Legend
Replies: 4
Views: 6380

Re: Axis Legend

Thank for the code, it Works. But i want that the values of the axe that not always is the same as the bars to be with the €
by Fulcrum
Fri Jun 28, 2013 7:53 am
Forum: .NET
Topic: Legend
Replies: 8
Views: 10461

Re: Legend

i have 10 values
by Fulcrum
Thu Jun 27, 2013 9:16 am
Forum: .NET
Topic: Legend
Replies: 8
Views: 10461

Re: Legend

I have probed it and only shows 5 parts
by Fulcrum
Thu Jun 27, 2013 7:43 am
Forum: .NET
Topic: Axis Legend
Replies: 4
Views: 6380

Axis Legend

Hello,
I have a Bar Chart and i wanted to put in the Y axis the values with the € simbol.
Is this posible?
by Fulcrum
Wed Jun 26, 2013 12:08 pm
Forum: .NET
Topic: Legend
Replies: 8
Views: 10461

Re: Legend

Hello Sandra,

with this propertie the legend only show 5 of the parts, and the rest dissapears
by Fulcrum
Wed Jun 26, 2013 12:04 pm
Forum: .NET
Topic: Gradient
Replies: 18
Views: 21587

Re: Gradient

Ok, it Works now.

Thanks for the help.
by Fulcrum
Wed Jun 26, 2013 8:39 am
Forum: .NET
Topic: Legend
Replies: 8
Views: 10461

Legend

Hello, i have a pie chart with the legend at the bottom. What i would like is to put the legend elements in two colums to make it smaller
by Fulcrum
Wed Jun 26, 2013 8:36 am
Forum: .NET
Topic: Gradient
Replies: 18
Views: 21587

Re: Gradient

Code: Select all

 Dim bar As Steema.TeeChart.Styles.Bar = DirectCast(Chart(0), Steema.TeeChart.Styles.Bar)
says that chart isnt declared
by Fulcrum
Tue Jun 25, 2013 11:04 am
Forum: .NET
Topic: Gradient
Replies: 18
Views: 21587

Re: Gradient

Maybe i didnt explain correctly. The traslation to vb.net of this part of your code will be: Dim bar As Steema.TeeChart.Styles.Bar = DirectCast(Steema.TeeChart.Chart(0), Steema.TeeChart.Styles.Bar) bar.BarStyle = Steema.TeeChart.Styles.BarStyles.RectGradient bar.Gradient.StartColor = Color.Red bar.G...
by Fulcrum
Tue Jun 25, 2013 10:08 am
Forum: .NET
Topic: Gradient
Replies: 18
Views: 21587

Re: Gradient

Ok the code work but what i want is to change the gradient of the bar
by Fulcrum
Tue Jun 25, 2013 7:55 am
Forum: .NET
Topic: Gradient
Replies: 18
Views: 21587

Re: Gradient

In your example tou have the chart and you add the series in the function,
I want to have the series in the chart before you call the function
by Fulcrum
Fri Jun 21, 2013 12:10 pm
Forum: .NET
Topic: Gradient
Replies: 18
Views: 21587

Re: Gradient

I want a function that passing a chart with the series, it sets the gradient and other features of the chart
by Fulcrum
Fri Jun 21, 2013 11:43 am
Forum: .NET
Topic: Gradient
Replies: 18
Views: 21587

Re: Gradient

Sorry, the real code is Steema.TeeChart.Chart Chart1; Steema.TeeChart.Chart Chart2; Steema.TeeChart.Chart Chart3; Steema.TeeChart.Styles.Bar bar1 = new Steema.TeeChart.Styles.Bar(tChart1.Chart); Steema.TeeChart.Styles.Bar bar2 = new Steema.TeeChart.Styles.Bar(tChart2.Chart); Steema.TeeChart.Styles.B...
by Fulcrum
Fri Jun 21, 2013 9:53 am
Forum: .NET
Topic: Gradient
Replies: 18
Views: 21587

Re: Gradient

what i want is a function that puts the format to the chart: Steema.TeeChart.Styles.Bar bar1 = new Steema.TeeChart.Styles.Bar(tChart1.Chart); Steema.TeeChart.Styles.Bar bar2 = new Steema.TeeChart.Styles.Bar(tChart2.Chart); Steema.TeeChart.Styles.Bar bar3 = new Steema.TeeChart.Styles.Bar(tChart3.Char...